-0.0015x^2+60=-0.002x+18

Solution for -0.0015x^2+60=-0.002x+18 equation:

-0.0015x^2+60=-0.002x+18

We move all terms to the left:

-0.0015x^2+60-(-0.002x+18)=0

We get rid of parentheses

-0.0015x^2+0.002x-18+60=0

We add all the numbers together, and all the variables

-0.0015x^2+0.002x+42=0

a = -0.0015; b = 0.002; c = +42;
Δ = b2-4ac
Δ = 0.0022-4·(-0.0015)·42
Δ = 0.252004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.002)-\sqrt{0.252004}}{2*-0.0015}=\frac{-0.002-\sqrt{0.252004}}{-0.003}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.002)+\sqrt{0.252004}}{2*-0.0015}=\frac{-0.002+\sqrt{0.252004}}{-0.003}
$